Hello, I'm interested in purchasing a bit of code. Right now I have a Symfony 2-based site up and running and I'd like to add the information I need for every (or as many as possible) adult site. All I really need is this information: $regexes[] = '(?:https?:\/\/(?:.+\.)vimeo.com(?:\/video\/|(?:.+clip_id=))([a-z0-9-]+))'; and this information: //vimeo video ids will go on matches[2] foreach (array_unique($matches[2]) as $videoId) { if (empty($videoId)) { continue; } //get video data $duration = 0; $videoDataUrl = "http://vimeo.com/api/v2/video/{$videoId}.php"; $videoData = unserialize(file_get_contents($videoDataUrl)); if (!empty($videoData[0])) { $thumbUrl = $videoData[0]['thumbnail_large']; $videoUrl = $videoData[0]['url']; //type 2 now hardcoded, we should create a VideoResourceFetcher $urls[] = array('type' => 2, 'url' => $thumbUrl, 'src_th_url' => $videoUrl, 'duration' => $duration); } ...but for every adult video site in existence. (Or at least an even dozen of them.) I don't need it to download videos for me... I don't need it to do anything at all really. I just need that information for all the adult sites. Let me know if you think you can help. Keywords: Vimeo, Multimedia, Website, PHP, Adult, Symfony, Video